17 July 2017, Comments Comments Off on comparing similar ages, statistics homework help

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Question description
•Section 2.1
26a) https://www.youtube.com/watch?v=uqyblkTQ1mA –> bar graph video

•Section 2.2
9a) – 9e)
55) % change = difference in the %amounts / beginning %amount = Dec % – Jan % / Jan %
60) For each variable, explain the type of graphical summary you might be able to draw to provide a visual summary of the data. –> Ex: Age you can use a histogram or stem-and-leaf; ect

•Section 2.3
6) Look at the ages – are they comparing similar ages?
8a) look at the vertical axis – is there an issue with it?
8b) look at the years do you see any discrepancies?

•Section 3.1
24a) median -> make sure you put the data in order first:
24b) median –> make sure you put the data in order first:
16) mean: => Sum / n median: => make sure you put in order first
mode: => most that occurred?

34) multiply the students height by 14 and then add in the other and divide by the total number of students:

•Section 3.2
36a) formula: (1 – 1/k^2)*100%:
36b) formula: (1 – 1/k^2)*100%:
36c) formula: (1 – 1/k^2)*100%:

40) If all values in the data set are identical, then will there be any variance?
•Section 3.3
4) the mean and standard deviationMean: u =
The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

Standard Deviation:
set up this chart:
Class Midpoint Xi frequency, fi Xi fi x^2 i xi^2 fi
0-17 0+18/2 = 9 15,451 139,059 81 1,251,531
18-24 18+25 / 2 = 21.5 6,071 130,526.5 462.25 2,806,319.75
65 and older
find these sums Sum fi Sum Xi Fi Sum xi^2 fi
Then you can use these numbers to plug in the formula for standard deviation.

12) Cost per pound: Xbar = SumWiXi / Sum Wi
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